CSIR NET Exam 2024: Latest News, Eligibility, Salary & Vacancies
Table of Contents
Table of Contents
The Joint CSIR NET is a test being held to examine the eligibility of Indian nationals for Junior Research Fellowship (JRF) and Lectureship (LS)/Assistant Professor in Indian institutions and colleges that meet the UGC eligibility requirements. The Council of Scientific and Industrial Research (CSIR) has tasked the National Testing Agency (NTA) with conducting the Joint CSIR-UGC NET December 2022 / June 2023 Examination under the Computer Based Test (CBT) format.
Latest Updates:
- The National Testing Agency (NTA) released the CSIR UGC NET Answer Key on 6th January 2024.
- National Testing Agency (NTA) has released the CSIR UGC NET 2023 Admit Card. Candidates who applied for Joint CSIR-UGC NET Examination which will be conducted on 26th-28th December 2023 can download the admit card through the official website of CSIR UGC NET at csirnet.nta.ac.in.
- CSIR NET Exam to be conducted from 26th to 28th December 2023.
- Registration for CSIR NET 2023-24 starts on 1st November and ends on 30th November 2023.
About CSIR
The Council of Scientific and Industrial Research (CSIR) is a modern R&D organization noted for its cutting-edge R&D knowledge base in several S&T domains. CSIR and UGC provide Research Fellowships for training in research methodologies under the professional direction of faculty members/scientists working in university departments, national laboratories, and institutions in various scientific subjects.
Oceanography, geophysics, chemicals, medicines, genomics, biotechnology, and nanotechnology are all covered by CSIR, and mining, aeronautics, instrumentation, environmental engineering, and information technology. It offers considerable technology involvement in many social initiatives, including the environment, health, drinking water, food, housing, energy, and farm and non-farm sectors. Furthermore, CSIR’s contribution to S&T’s human resource development is notable.
CSIR NET Exam: Overview
| Particulars | Elaboration |
| Exam | Council of Scientific and Industrial Research National Eligibility Test (CSIR NET) |
| Conducted By | Exam Level |
| Examination purpose | To determine applicants’ eligibility for Junior Research Fellowship (JRF) and Lectureship (LS)/ Assistant Professor at Indian institutions and colleges. |
| Exam Level | National level |
| Exam Centres | 225 |
| Examination frequency | Twice a year |
| Mode of Exam | Online – Computer-Based Test (CBT) |
| Medium of Exam | English and Hindi |
| No. of papers | 2 |
| Application Mode | Online |
| Online – Computer-Based Test (CBT) | INR 1,100 for the General category INR 550 for OBC INR 275 for SC/ ST INR 0 for PwD |
| Exam Duration | 3 Hours (180 Minutes) |
| Exam Shift | Shift 1 – 09:00 am to 12:00 noon Shift 2 – 03:00 pm to 06:00 pm |
| No. of Questions | 150 MCQ in each Paper |
| Total Marks | Paper 1- 200 Paper 2- 200 |
| Marking Schemes | +2 for each correct answer 0.25 mark deduction for each wrong answer |
| Exam Help Desk Number | 0120-6895200 |
| Official website | https://csirnet.nta.nic.in/ https://nta.ac.in/ |
CSIR NET Notification 2024
The NTA has not yet released the CSIR NET Application Form 2024 and the announcement. For the convenience of applicants, significant features of the CSIR NET Notification 2024 are provided below.
For JRF and LS/AP CSIR, CSIR NET online applications are available twice a year via the official website. Candidates who pass the exam will be qualified to apply for the position of Lecturer in the discipline under the faculty of Science and Technology at various universities and colleges in India. The candidates who meet the Junior Research Fellowship (JRF) requirements will be eligible to apply for a PhD in their chosen fields at various Indian universities. JRF students are eligible for various benefits, including stipends, HRAs, etc.
CSIR NET 2024 Exam Dates
The exam schedule for all disciplines will be posted on the CSIR website soon.
| Particulars | Dates |
| CSIR NET Notification | To Be Notified |
| CSIR NET Application Form | To Be Notified |
| CSIR NET Application Form (Last date of Submission) | To Be Notified |
| CSIR NET Application Form (Correction Window) | To Be Notified |
| CSIR NET Admit Card | To Be Notified |
| CSIR NET Exam Date | To Be Notified |
| CSIR NET Provisional Answer Key Release | January 2024 |
| CSIR NET Objection Window Provisional Answer Key | To Be Notified |
| CSIR NET Final Answer Key 2023 | 6th January 2024 |
| CSIR NET Result | January 2024 |
The CSIR NET 2024 test will most likely be administered in two sessions. See the entire schedule below:
| CSIR NET Exam Day Events | CSIR NET 2024 First Shift Timings | CSIR NET 2024 Second Shift Timings |
|---|---|---|
| Timing of exam | 9:00 AM-12:00 PM | 3:00 PM-6:00 PM |
| Duration of exam | 3 hours without a break | 3 hours without break |
| Entry into the exam centre | 7:00-8:00 AM | 1:00-2:00 PM |
| Entry into the exam hall/room | 8:15-8:30 AM | 2:15-2:30 PM |
| Checking of admit cards by the invigilator | 8:30-8:45 AM | 2:30-2:45 PM |
| Sitting on the seat in the exam hall | 8:45 AM | 2:45 PM |
| Instructions by the invigilators | 8:45-8:55 AM | 2:45-2:55 PM |
| Test commences | 9:00 AM | 3:00 PM |
| Test concludes | 12:00 PM | 6:00 PM |
The NTA releases the CSIR NET admission card a few days before the exam. Candidates may get their CSIR NET 2024 admit card by entering their registered accounts on the exam’s official website.
CSIR NET Eligibility Criteria
Candidates who wish to register for the CSIR-UGC NET 2024 examination must check the eligibility criteria. The NTA (National Testing Agency) determines the qualifying conditions based on age, educational qualifications, and country.
Nationality
- Only Indian citizens are eligible to apply for the CSIR NET 2024 Test.
- If an applicant is discovered to be ineligible, his or her application form will be rejected.
Educational Qualification
Candidates must have either of the following credentials with at least 55% (for General and OBC) or 50% (for Scheduled Caste (SC)/Scheduled Tribe (ST)/Persons with Disability (PwD) candidates).
- Candidates who are enrolled in MSc or have completed 10-2-3 years of MSc or equivalent degree/Integrated BS-MS/BS-4 years/BE/B Tech/ B Pharma/ MBBS as of the CSIR NET application deadline 2023 are also eligible to apply under the Result Awaited (RA) category. However, the requirement for RA category applicants is to finish their qualifying degree with the requisite percentage of marks within two years after the announcement date of the Joint CSIR UGC NET result, failing which they would be disqualified.
- Candidates with a Ph.D. and a master’s degree completed before September 19, 1991, with at least 50% marks, can apply for lectureships alone.
- Candidates with a BSc (Hons) or equivalent degree or those enrolled in an integrated MS-PhD program must have at least 55% (or 50% for SC/ST/PwD students) to apply for the test. On the other hand, candidates with an undergraduate degree will be eligible for a CSIR fellowship only after enrolling in a Ph.D./Integrated PhD course within the validity period of two years, according to the official website.
- Candidates with only a Bachelor’s degree are only eligible to apply for the Junior Research Fellowship (JRF), not the Lectureship (LS)/Assistant Professor. BE/BS/B Tech/B Pharma/MBBS final year/result awaiting applicants, for example, are only eligible to apply for JRF.
Eligibility Criteria: Subject-wise
The table below details the CSIR NET 2024 Educational Qualification by subject:
| Subject | Qualification Required |
| Chemical Science | Candidates must have an MSc/BS/B-Tech degree in Chemistry or an equivalent qualification. |
| Earth, Ocean, Atmospheric and Planetary Science | Candidates must have an MSc/BS-MS/BS-4 Years/B-Pharma or an equivalent degree in Earth, Ocean, Atmospheric, and Planetary Science. |
| Life Science | Candidates with academic qualifications in Life Sciences are required. |
| Mathematics | Candidates must have an MSc/BS-MS/BS/B-Tech degree in Mathematics or an equivalent qualification. |
| Physical Science | Candidates must have an MSc in Physics or a BS-MS in Physics, or an equivalent certificate. |
Age Limitation
As of July 1, 2023, the maximum age restriction for the granting of a Joint Research Fellowship (JRF) is 28 years.
- Candidates applying for CSIR NET lectureships have no upper age limit.
- The upper age restriction for reserved category candidates (SC/ST/PwD and female applicants) may be lowered by up to 5 years and 3 years for OBC – Non-creamy layer candidates.
| Category | Age Limit |
| SC/ ST/ PwD/ Female | 33- years |
| OBC (non-creamy layer) | 31- years |
Candidates may also examine the age-related relaxation for candidates from the restricted categories.
| Category | Age Limit Relaxation Years |
| Female | 5 |
| Scheduled Caste | 5 |
| Scheduled Tribe | 5 |
| OBC (non-creamy layer) | 3 |
| Persons with disability (PwD) | 5 |
Note: Some important points to remember
- Candidates who qualify for a Lectureship will be eligible for both Lecturer recruitment and a Junior Research Fellowship in a Scheme/Project, if otherwise qualified. They will, however, be ineligible for Regular JRF-NET Fellowship.
- Candidates for the JRF (NET) grant will get a fellowship from CSIR or UGC based on their assignment or schemes with which they may find an affiliation.
- Candidates considered eligible for Junior Research Fellowships and Lectureships under the UGC scheme would be subject to UGC rules and regulations in this respect.
Reservation Criteria 2024
The CSIR has established criteria for reducing the minimum marks necessary and the maximum age limit for candidates from various reserved categories (SC/ST/OBC-NCL/PwD) and female applicants.
In terms of categories CSIR NET, the following table details the relaxation of marks for qualified applicants from reserved categories:
| Category | Marks Relaxation Percentage |
| Other Backward Classes | 5% |
| Scheduled Caste | 5% |
| Scheduled Tribe | 5% |
Junior Research Fellowship and Lectureship Selection
Candidates must indicate whether they are applying for JRF or LS positions based on their eligibility and indicate their preference in this manner on the CSIR UGC NET application form.
- A candidate who applies for JRF and meets the requirements for a Lectureship will also be considered for JRF & LS.
- A candidate will only be considered for Lectureship (NET) if it is determined that they are too old for JRF (NET).
- The candidate’s selection or choice on the application form is final, and requests for changes will not be taken into consideration subsequently.
- The number of candidates who pass the exam depends on the number of fellowships available and their performance in the exam, provided they meet the requirements for eligibility.
- Candidates who hold a M.Sc. degree or fall under the M.Sc. Result Awaited (RA) category is eligible for lectureships (LS), provided they meet the UGC’s eligibility requirements.
CSIR NET Exam Application Form
The NTA will release the CSIR NET 2024 Notification and the CSIR NET Application Form 2024 on the official website csirnet.nta.nic.in.
Candidates are advised to be careful to finish their payment since no application will be approved without payment of the required fee.
CSIR NET Application Fee 2024
The entire CSIR Net 2024 Application Fee per category is shown below. No application will be deemed submitted without payment of the fee. The CSIR NET application cost must be paid online by debit card, credit card, or internet banking by applicants. The application fee is broken down per type as follows.
| Category | Application Fee (Rs.) |
| General | 1100 |
| OBC (Non-creamy layer) | 550 |
| SC/ST/Third Gender | 275 |
| PwD | Nil |
How to Apply for CSIR UGC NET?
Candidates can complete the CSIR NET online form 2024 by following the instructions below:
Step 1: Sign up / Register for CSIR- UGC NET 2024.
Candidates must follow the actions listed below to register online:
- Visit the examination’s official website at csirnet.nta.nic.in.
- To access the link to complete the application, click it.
- Select “New Registration” from the menu.
- Read the page’s instructions carefully after downloading the CSIR NET information pamphlet.
- Click the “Click Here to Proceed” button after selecting the checkbox at the bottom of the page.
- After pressing the button, the CSIR NET registration form will appear on the screen.
- Complete the registration form by providing all the information requested.
| Personal Details | |
| Name | Date Of Birth |
| Parents Name | ID Type |
| Gender | ID Card Number |
| Contact Details | |
| Permanent Address | Mobile Number |
| Email ID | |
- Select a password.
- Select a security query.
- Then input the security response to the security pin that is displayed on the screen.
- Select “Submit”
- Check the information you have provided by selecting the checkboxes at the bottom of the page.
- Select “Final Submit” from the menu.
Step 2: Complete the CSIR- UGC NET application
Candidates must click the “Complete Application Form” option to continue filling out the CSIR UGC NET online application form. The information that applicants must include in the form is listed below.
- Fill in the security code that appears on the screen.
- Select “Submit”
- Check the information you’ve entered by selecting the checkboxes at the bottom of the page.
- Select “Final Submit” from the menu.
Step 3: Upload Your Scanned Signature and Photo
Candidates must next upload scanned copies of their signature and photo according to the guidelines.
| Documents | Uploading Format | Size (in KB) |
| Signature | JPG | 4KB – 30KB |
| Photograph | JPG | 10KB – 200KB |
Step 4: CSIR- UGC NET Application Fee must be Paid
Upon successful payment of the charge, a confirmation page will be created. The confirmation page must be printed at least three times by candidates, and they must save all copies for their records.
Required Documents for CSIR- UGC NET Application
The CSIR- UGC NET 2024 application form must be completed with the following details and supporting documentation:
- A valid email address
- A functioning mobile number
- Class 10, 12, graduation, and post-graduate transcripts
- A scanned copy of a passport-sized picture
- A scanned copy of your signature and, if necessary, a disability certificate.
- Banking information is required to pay the charge.
Correction to Application Form
- Soon after registration is complete, NTA will offer a service for CSIR NET Application Form Correction.
- The official website, csirnet.nta.nic.in, is the only place where the online Application Form Correction service is available.
- Additionally, NTA informs candidates through email and SMS about form and appearance modification.
- Candidates can change or alter areas including name, parents’ names, date of birth, contact information, category, and gender.
- To make modifications, candidates must supply supporting documentation and, if applicable, pay additional costs.
- This is the final opportunity to modify and improve the application form. No more requests will be granted.
Login Procedures after Forgetting Password
- The candidates must initially respond to the security question.
- Give the verification code that will be given by text message to the applicants’ registered cell phone number.
- Use the reset connection link that will be provided to the applicant’s registered email address.
A few days before the test, the CSIR UGC NET admit card will be made accessible. The admission card will provide further information about the schedules, exam location, and other factors.
CSIR NET Admit Card 2024
Candidates who plan to sit for the exam must bring the CSIR NET Admit Card and an original picture ID evidence to the exam site. The CSIR NET 2024 admit card must be brought to the designated test location. Candidates who do not have their admission card when it is needed might not be allowed to attend the exam paper.
NTA does not distribute hall tickets through mail, courier, or email. It will be accessible online at the CSIR’s main website.
How to Download CSIR NET Exam Admit Card?
Applicants to download their CSIR UGC NET test admission cards may use the procedures listed below:
- Step 1: Go to the NTA’s official website.
- Step 2: Select the ‘CSIR NET Admit Card link.
- Step 3: Key in the application number, birth date, and security code (as seen in the illustration).
- Step 4: Click the Login button.
- Step 5: Select “Download Admit Card” from the menu.
- Step 6: Download the admission card, save it, and print it.
Details Available on CSIR- UGC NET Exam Admit Card
The admission card includes the following information regarding the applicant and test.
- Candidate’s name
- Candidate’s roll number
- Candidate’s photo
- Candidate’s signature
- CSIR NET exam slot and time
- Time of reporting at the test centre
- CSIR NET exam centre name
- CSIR NET exam centre address
Items Permitted at the Exam Centre 2024
Candidates to the CSIR NET testing sites may bring the following objects:
- Personal Water Bottle (Transparent).
- A simple transparent Ball Point Pen
- Personal hand sanitiser (50 ml)
- Self Declaration (Undertaking) and CSIR NET admission card retrieved from the NTA website.
- Another passport-size picture
- Original ID evidence
- No candidate may enter the centre while donning his or her mask. The centre will supply the facemask.
CSIR NET Syllabus
The NET syllabus is public by the CSIR on their official website. Candidates who plan to take the exam can download the PDF for the course materials for each of the five subjects and use them offline. The CSIR NET exam consists of three parts, A, B, and C. The Part A syllabus is the same for everyone, while the Part B and C syllabuses depend entirely on the candidates’ chosen subjects. Candidates can choose the subject when completing their online application.
The CSIR NET Syllabus is a collection of topics from various subjects for which the exam is given. All applicants must be familiar with the exam topics to improve their chances of selection. Part-A is based on General Science, Quantitative Reasoning and analysis, and Research Aptitude. Part B is based on the concerned subject and Part- C is based on the scientific concepts or their applications.
CSIR – UGC NET Subjects
| Subjects | Codes |
| Chemical Science | 701 |
| Earth, Atmospheric, Ocean, and Planetary Science | 702 |
| Life Science | 703 |
| Mathematical Science | 704 |
| Physical Science | 705 |
Details of the CSIR NET Syllabus 2024
| Chemical Sciences | Earth, Atmospheric, Ocean & Planetary Sciences | Life Sciences | Mathematical Sciences | Physical Sciences |
| Branches of Chemistry | Oceans and Atmosphere | Cellular Organization | Analysis | Mathematical Methods of Physics |
| Organic Chemistry | Environmental Earth Sciences | Inheritance Biology | Algebra | Atomic & Molecular Physics |
| Inorganic Chemistry | Mineralogy and Petrology | Developmental Biology | Classical Mechanics | Electromagnetic Theory |
| Medicinal Chemistry | The Earth and the Solar System | Molecules and their Interaction Relevant to Biology | Linear Integral Equations | Thermodynamic and Statistical Physics |
| Physical Chemistry | Earth Materials, Surface Features and Processes | Applied Biology | Calculus of Variations | Nuclear and Particle Physics |
| Catalysis and Green Chemistry | Geophysics | Diversity | Partial Differential Equations (PDEs) | Condensed Matter Physics |
| Chemistry in Nanoscience and Technology | Palaeontology and its applications | Fundamental Processes | Numerical Analysis | Quantum Mechanics |
| Supramolecular Chemistry | Marine Geology and Palaeontology | Evolution and Behaviour | Ordinary Differential Equations (ODEs) | Electronics and Experimental Methods |
CSIR NET Exam Pattern 2024
Exam questions for the CSIR UGC NET 2024 will be objective-type multiple-choice and asked from the applicants’ selected topic. View a summary of the test pattern in the table below.
| Particulars | Exam Pattern |
| Exam Mode | Online – Computer Based Test (CBT) |
| Exam Duration | 3 Hours (180 minutes) |
| Total Sections | 3 in each paper |
| Total Questions | Total Questions- 610 Need to Attempt- 310 |
| Types of Questions | MCQ: 4 options with 1 correct answer |
| Total Marks | 200 for each paper (Paper1 and Paper 2) |
| Negative Marking | Yes |
| Language | English and Hindi |
The test would be divided into three sections for each subject, which are covered in depth in the following sections:
- There will be 200 total marks awarded for each test.
- Each test will include three sections: Part A, Part B, and Part C.
- Each test has a different scoring scheme. Below, you can see the exam schedule for each exam.
| CSIR- UGC NET Marking Schemes (Subject-wise) | ||||
| Subjects | No. of Questions | To be attempted | Marking Scheme | Negative Marking |
| Chemical Sciences | 120 Part A- 20 Part B- 40 Part C- 60 | 75 Part A- 15 Part B- 35 Part C- 25 | 200 Part A- 2 Part B- 2 Part C- 4 | Part A- 0.5 Part B- 0.5 Part C- 1 |
| Earth, Atmospheric, Ocean, and Planetary Sciences | 150 Part A- 20 Part B- 50 Part C- 80 | 75 Part A- 15 Part B- 35 Part C- 25 | 200 Part A- 2 Part B- 2 Part C- 4 | Part A- 0.5 Part B- 0.5 Part C- 1.32 |
| Life Sciences | 145 Part A- 20 Part B- 50 Part C- 75 | 45 Part A- 15 Part B- 35 Part C- 25 | 200 Part A- 2 Part B- 2 Part C- 4 | Part A- 0.5 Part B- 0.5 Part C- 1 |
| Mathematical Sciences | 120 Part A- 20 Part B- 40 Part C- 60 | 60 Part A- 15 Part B- 25 Part C- 20 | 200 Part A- 2 Part B- 3 Part C- 4.75 | Part A- 0.5 Part B- 0.75 Part C- 0 |
| Physical Sciences | 75 Part A- 20 Part B- 25 Part C- 30 | 55 Part A- 15 Part B- 20 Part C- 20 | 200 Part A- 2 Part B- 3.5 Part C- 5 | Part A- 0.5 Part B- 0.875 Part C- 1.25 |
CSIR NET Exam Answer Key
On January 06, 2024, that year’s CSIR UGC NET tentative answer key was made available online at https://csirnet.nta.nic.in. The National Testing Agency (NTA) conducts the CSIR UGC NET(commonly known as CSIR NET) exam at the national level to select applicants for the award of Junior Research Fellowships (JRF).
Steps to Check the Answer Key
All candidates on the official website using the login information created during the registration process may see the CSIR NET Exam Answer Key. Candidates can use the procedures listed below to verify the CSIR NET answer key:
- Step 1: Go to the CSIR UGC NET official website. (http://csirnet.nta.nic.in)
- Step 2: To verify the answer key, click the link on the homepage. From the drop-down option, choose the CSIR NET answer key.
- Step 3: As shown on the screen, enter the required information, including the application number, password, and security pin.
- Step 4: Choose the Login button.
- Step 5: Keep the response sheet and answer key so you can figure out your projected grade.
How to Challenge the Answer Key?
Candidates can contest the CSIR NET Exam Answer Key 2024 by doing the following actions:
- Step 1: Go to the CSIR UGC NET official website.
- Step 2: Select the “Challenges Regarding Answer Key” link on the website’s home page.
- Step 3: A login screen will be presented to you. Once your Application Number, Password/Date of Birth, and Security Pin have been entered, click Submit.
- Step 4: Next, click the link to contest the solution key.
- Step 5: Select the appropriate response option ID for the question that has been challenged.
- Step 6: Press the Save Your Claims button to save your claims.
- Step 7: Upload the supporting documentation for your claim.
- Step 8: Press the ‘Save Your Claims & Pay Fee’ option to save your claims and pay the charge.
CSIR NET 2024 Result
After the CSIR NET 2024 test has been successfully administered, the National Testing Agency (NTA) will publish the results on its official website. Candidates may see their results by visiting the official website when the CSIR NET Results are released online. The candidates who passed the test will receive their eligibility certificates and JRF Award Letters from NTA following the announcement of the CSIR NET Result 2024. The job of Assistant Professor at Indian colleges and universities is also open to qualified people.
How to view the results?
Candidates can use the methods listed below to verify their CSIR UGC NET 2024 result:
Step 1: Go to CSIR NET’s official website.
Step 2: Select “Joint CSIR UGC NET June 2024 Score Card” from the list of links.
Step 3: Provide the following information.
- Application ID
- Date of Birth
- The security pin is seen in the picture
Step 4: Select “Submit.”
Step 5: View and save the CSIR NET scorecard and results.
How to Check Result if Application Number is forgotten?
If applicants forget their application number, they can obtain a new one on the exam’s official website by following the instructions below:
Step 1: Explore the CSIR NET website.
Step 2: Select the link for the result.
Step 3: Select the ‘Forgot Application No.’ link.
Step 4: Type in the information below:
- Name
- Name of the mother and father
- Date of birth
- Security pin (as shown on the screen)
Step 5: Press the button labelled “Get Application Number.”
After the CSIR- UGC NET Results, what comes next?
In due order, NTA issues eligibility certificates and JRF award letters to candidates who complete the CSIR NET exam. Then, all qualified individuals can apply for an assistant professorship at an Indian university or college or do research in the field of science of their choice.
CSIR NET Certificate
On the official website, certificate.nta.ac.in, the NTA has made the CSIR UGC NET 2024 certifications available. Candidates may now use the below-listed procedure to get their CSIR NET certificate for 2024.
CSIR NET Salary Structure
Candidates interested in a teaching and research career should take the CSIR NET test. After passing this admission exam, the chosen individual can pursue a PhD at a reputable university. If you pass the NET JRF exam, you are qualified for the numerous occupations listed in the table below.
| Job Position | Monthly Expected Salary (in INR) |
| Junior Research Fellows | 31,000 +HRA (Depends on the Institution) |
| Senior Research Fellows | 35,000+HRA (Depends on the Institution) |
| Assistant Professor | 45,000 |
| Associate Professor | 80,000 |
| Professor | 82,000 |
For the first two years, a JRF selected through CSIR-NET will receive a monthly stipend of Rs.31000. A yearly contingent grant of Rs.20000 will also be given to the university or institution for each fellow. The terms and conditions of the CSIR, UGC, or Research Scheme, as appropriate, will govern the Fellowship. The Fellowship will be upgraded to SRF (NET) after two years as JRF.
If the Fellow is enrolled in a PhD, the stipend will be increased to Rs. 35,000/- per month for the third and subsequent years, based on an assessment of the Fellow’s research progress/achievements through an interview by an Expert Committee consisting of the Guide, Head of the Department, and External Member from outside the University/Institute who is an expert in the relevant field.
CSIR NET Cut-Off
The CSIR NET Cut-Off is the score at which candidates will be chosen for JRF and Lectureship positions. To pass the CSIR NET exam, candidates must score at least 33% in the General, EWS, and OBC categories and 25% in the SC, ST, and PwD categories. There are three parts to the CSIR UGC NET: Parts A, B, and C. However, there are no sectional cut-offs; instead, the cut-off is determined by adding the marks obtained in each component. The cut-off marks vary for both the categories, Junior Research Fellowship (JRF) and Lectureship.
| CSIR NET JRF Cut-off (Expected) | ||||||
| Subject | UR (%) | EWS (%) | OBC (%) | SC (%) | ST (%) | PWD (%) |
| Chemical Science | 52.75 | 46.25 | 45.5 | 36.25 | 27.25 | 25 |
| Earth Science | 60.86 | 54.79 | 53.06 | 46.4 | 42.81 | 26.4 |
| Life Science | 98.78 | 96.06 | 96.22 | 90.53 | 84.87 | 64.76 |
| Mathematical Science | 49.25 | 44.87 | 42.75 | 34.37 | 27 | 25 |
| Physical Science | 38.81 | 33 | 33 | 25 | 25 | 25 |
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FAQs
Candidates can retrieve their UGC NET application number or password for CSIR NET online if they have forgotten it. To retrieve your Application Number/Roll Number or Password, follow the steps listed below:
1.) Visit the official website.
2.) Select the button for the application form.
3.) Select the link labelled “Forgot Application Number.”
4.) Enter your name, father’s name, mother’s name and date of birth.
5.) Enter the security pin shown on the screen.
6.) The “Get Application Number” button should be clicked.
The National Eligibility Test (NET), administered on behalf of the University Grants Commission (UGC), determines whether Indian citizens are eligible for assistant professor positions in Indian universities and colleges. NTA administers CSIR NET to select candidates for the JRF award and eligibility for assistant professor positions in science-only fields. NTA administers UGC NET to choose candidates for JRF awards and eligibility for assistant professor positions in all other subjects (total of 81).
The CSIR NET exam is considered to be highly competitive and tough. While studying for the exam, you gain much knowledge and experience, so passing it is not just like having a degree. With others, you can impart your wisdom and experience. Candidates who pass the CSIR NET examination can apply for junior research fellowships and teaching positions. The NET exam is held twice a year, in June and December, by NTA on behalf of UGC. To sit for this exam, candidates must have earned a minimum of 55% on their Master’s degree. Candidates who pass the UGC NET exam are eligible for lecturer positions at IITs and NITs as well as research programs (JRF)
The overall NTA score represents the proportion of candidates who, in that session, scored EQUAL TO OR BELOW (same or lower raw scores) that specific candidate. It says nothing about your qualifications or lack thereof. Most likely, the cut-off will be the same as last year. But it should be increased by five marks (Not a percentage). According to the CSIR NET answer key, marks will be awarded for accurate responses. This raw score will create the “NTA score” or percentile. All candidates’ scores will be combined to create the final merit list.
Four to five months after the results are announced, UGC and CSIR upload the certificate. Candidates who qualify for lectureships and research positions as JRFS in Indian universities are given this certificate. To download CSIR certificates, follow these simple steps:
1: Sign in to the CSIR website.
2: Enter the required details as mentioned on the website and press the “submit” button.
3: Download the CSIR certificate visible on the screen.
4: Print the hard copy later for your records.
Download Certificate (Part II and III)
1: Access the UGC website.
2: Press the button to download the CSIR-UGC Test e-certificate.
3: There will then be a “Yes” or “No” option for you to select.
4: Click “Yes” if you already have your password via OTP.
5: If you haven’t received the password via OTP, choose No.
6: Complete all the necessary information and download the certificate.