CSIR net

CSIR UGC NET Exam 2022: Latest News, Eligibility, Salary & Vacancies

October 4, 2022

Table of Contents

Table of Contents

What is CSIR UGC NET?

The National Testing Agency leads CSIR UGC NET on the Council of Scientific and Industrial Research (CSIR) mandates. In order to determine whether Indian citizens are qualified for Junior Research Fellowships (JRF) and Lectureships (LS)/Assistant Professor Positions in Indian universities and colleges, the Joint CSIR UGC NET test is being administered. For training in research techniques under the expert supervision of professors and scientists working in university departments, national laboratories, and institutions across a range of scientific disciplines, CSIR and UGC offer Research Fellowships.

The exam is also known as CSIR NET. It’s a National Level exam conducted by the NTA. CSIR – UGC Net is done in CBT (Computer Based Test) mode only. For JRF and LS/AP CSIR, CSIR NET online applications are made available twice a year via CSIR Press Notification on all Indian CSIR UGC NET websites. Under the expert direction of faculty or researchers working in university departments, national laboratories, and institutions across a variety of scientific fields, UGC offers Research Fellowships to train techniques for research. Only legitimate Indian citizens are permitted to take the exam. NTA CSIR NET Fellowship is a workable remedy in India. The development of national science and technology human resources is the aim of this program.

Important Details About UGC NET

Candidates who pass the exam will be qualified to apply for the position of Lecturer in the discipline under the faculty of Science and Technology at various universities and colleges in India. The candidates who meet the requirements for the Junior Research Fellowship (JRF) will be eligible to apply for a PhD in their chosen fields at various Indian universities. JRF students are eligible for a variety of benefits, including stipends, HRAs, and others.

For the first two years, a JRF selected through CSIR-NET will receive a stipend of Rs.31, 000 per month. A yearly contingent grant of Rs.20, 000 will also be given to the university or institution for each fellow. The terms and conditions of the CSIR, UGC, or Research Scheme, as appropriate, will govern the Fellowship. The Fellowship will be upgraded to SRF (NET) upon completion of two years as JRF and if the Fellow is enrolled in a Ph.D., and the stipend will be increased to Rs. 35,000/- per month for the third and subsequent years, on the basis of assessment of the Fellows’ research progress/achievements through interview by an Expert Committee consisting of the Guide, Head of the Department, and External Member from outside the University/Institute who is an expert in the relevant field.

UGC NET Exam Overview

ParticularsDetails
Examination NameCSIR-UGC NET
Exam Conducting BodyNTA (National Testing Agency)
Examination LevelNational
Posts OfferingJunior Research Fellowship and Lectureship
Examination ModeOnline
Periodicity(No. of time)Twice a year  – June and December
Application ModeOnline
Examination ModeComputer Based Test (CBT)Online
Language of PaperEnglish and Hindi
No. of Test Cities225
Helpdesk No.0120-6895200
Official Websitehttp://csirnet.nta.nic.in, http://nta.ac.in/

CSIR UGC NET Selection Process 2022

The candidates who are going to appear in CSIR UGC NET 2022 exam must know the selection process of the examination. Hence, only then can they understand that the step-by-step guide of the CSIR UGC NET selection process consists of the following stages given below:

  • Submit the application form of UGC NET successfully.
  • Appear in CSIR-UGC NET Exam.
  • Qualify in the Exam.
  • The candidate who qualifies for the exam gets awarded a Junior Research Fellowship.

CSIR UGC NET 2022 Junior Research Fellow Selection Criteria

Junior Research Fellow2022 list of selected students in UGC NET exam (General Category) for Lectureship in English SubjectThe number of candidates (General category) who secure a minimum of 40% aggregate marks in papers 1 & 2 taken for ‘English’ (x) Total number of slots available under General category (÷) Total number of candidates (General category) overall subjects who secure at least 40% aggregate marks in both papers combined.

CSIR UGC NET 2022 Lectureship Selection Criteria

LectureshipList of selected students in UGC NET exam(General Category) for Lectureship in English SubjectThe number of candidates (General category) who secure a minimum of 40% aggregate marks in papers 1 & 2 taken for ‘English’ (x) Total number of slots available under General category (÷) Total number of candidates (General category) overall subjects who secure at least 40% aggregate marks in both papers combined.

The minimum score required to pass the UGC NET exam are given below:

  1. Candidates in the General category must receive 40% on each of the two papers to qualify for the UGC NET.
  2. The OBC category’s UGC NET qualifying score is 35%, which is different from the score for candidates in the reserved category.

Exam Notification and News

On 11th July 2022, the NTA made the CSIR NET 2022 announcement. The CSIR NET notification for 2022 has been made available on the National Testing Agency’s (NTA) official website, csirnet.nta.nic.in. The notification includes all of the crucial exam information, including the thorough application process, eligibility requirements, admit card, exam dates, exam schedule, syllabus, and others.

Three to four days before the test, the CSIR NET admit card for 2022 will be made available. From 11th July to 17th August 2022, candidates who wanted to be eligible for JRF and Lectureship/ Assistant Professor positions in Indian universities and colleges could apply for the CSIR NET.

CSIR UGC NET Exam Date 2022-23

The CSIR NET exam date has been mentioned below in the table:

EventsDates
CSIR UGC NET Notification11th July 2022
CSIR UGC NET Online Applications Starts11th July to 10th August 2022
Last date for payment of the application fee17th August 2022
Online Applications Correction Window19th August to 23rd August 2022
CSIR UGC NET Admit card 2022To be Announced
CSIR UGC NET exam 202216th September to 19th September 2022
CSIR UGC NET Result declaration 2022To be Announced
Provisional Answer KeyTo be Announced
Cut offTo be Announced

CSIR UGC NET Application Form

The four stages of the CSIR NET application for 2022 are registration, application, document upload, and fee payment. Candidates are advised to confirm that they meet the CSIR NET eligibility requirements 2022 before submitting their application for the CSIR NET 2022 exam.

STEP 1: Register for CSIR NET 2022

The steps listed below must be followed by candidates in order to register online:

  1. Visit the examination’s official website at csirnet.nta.nic.in.
  2. To fill out the application form, click the provided link.
  3. Select “New Registration” from the menu.
  4. Read the page’s instructions carefully after downloading the CSIR NET information brochure.
  5. Click the “Click Here to Proceed” button after selecting the checkbox at the bottom of the page. The CSIR NET registration form will appear on the screen after clicking the button.
  6. Complete the registration form by providing all the information requested.

STEP 2: Fill application form

Candidates must click the “Complete Application Form” button to continue filling out the CSIR UGC NET online application. Candidates need to fill the details like their personal details, educational qualification, exam center city, medium of exam, doctorate details (if any), etc.

STEP 3: Upload photo and signature

Candidates must upload scanned copies of their photo and signature that adhere to the requirements.

STEP 4: Payment

The CSIR UGC NET 2022 application fee must be paid online via a debit card, credit card, net banking, UPI, or Paytm gateway.

CSIR UGC NET Application Fee

Most importantly, there is an application fee for the candidates who want to appear in the CSIR-UGC NET 2022 exam. The examination conducting body accepts applications and the application fees through online mode only. The application fees can be submitted online through the official website only after filling out the application form.

Therefore, candidates must check all the information one more time before hitting the submit button while paying the application fee. The table below lists the application fees for various categories:

CategoryApplication fee (Rs)
GeneralRs 1000
EWSRs 500
OBC (Non-Creamy Layer)Rs 500
SC/ST/PDRs 250
PWDRs 250
TransgenderRs 250

CSIR UGC NET Eligibility Criteria

Candidates who wish to register for the CSIR-UGC NET 2022 examination must check the eligibility criteria. Those who fill out the form without passing the eligibility criteria will not download the admit card as they will fail the eligibility criteria. It’s essential to match the eligibility criteria if you wish to sit for the examination. The basic criteria are based on JRF age limit and educational qualifications.

The council establishes eligibility based on exam requirements and to ensure that all applicants have an equal chance.

Nationality

  • A citizen of India is required for the position.
  • Any candidate who is found to be in violation will have their application form rejected.

CSIR – UGC NET Age Limit

The age should be calculated as of 01st July, 2022.

Profile

Upper Age Limit

Reserved Category

SC/ST/PWD

OBC (NCL)

JRF

28 years

33 years

31 years

Assistant Professor

There is no Upper Age Limit

CSIR – UGC NET Educational Qualification

For General CategoryCandidates must have at least 55% marks in M.Sc. or Integrated BS-MS
For SC/ST/OBC CategoryCandidates of the SC/ST/OBC category must have a minimum score of 50% in M.Sc. or B.Sc. with admission in Integrated MS-PhD.

Subject-Specific Qualification for CSIR NET 2022

CSIR NET Subject-wise Qualification

Life Science

Pursued academic qualification in Life Science only.

Chemical Sciences

Have an M.Sc./BS/B-Tech or similar degree in Chemistry with the required percentage.

Earth Sciences

Within the required qualifying criteria, pursued an M.Sc./BS-MS/BS-4 Years/B-Pharma or any similar degree in the subject of Earth Science.

Mathematical Sciences

To meet the qualifying requirements, must have an M.Sc./BS-MS/BS-4 Years//B-Tech or an equivalent degree in mathematics.

Physical Sciences

Have a valid M.Sc. Physics or BS-MS in Physics degree, or any equivalent degree within the required percentage.

Number of attempts: There is no restriction on the number of attempts for the CSIR NET Exam provided candidates satisfy the eligibility criteria mentioned above.

CSIR UGC NET Salary

In particular, the Bhabha Atomic Research Centre (BARC), the National Environmental Engineering Research Institute (NEERI), the Indian Space Research Organization (ISRO), and the Council of Scientific & Industrial Research (CSIR), IMTECH, NBRI, ICAR, IGCAR itself can be entered after passing the NTA CSIR NET. Candidates can apply to different scientist grades like Scientist B, Scientist C, and Scientist D, career in managerial positions, conduct research for esteemed organisations, or develop and test products in the fields of medicine, pharmaceuticals, and consumer research. Below is a detailed list of the various grades of scientists and their pay scale:

Designation/ PositionPay range/ Scale
Scientist BINR 15,600 – 39,100
Scientist CINR 15,600 – 39,100
Scientist DINR 15,600 – 39,100
Scientist EINR 37,400 – 67,000
Scientist FINR 37,400 – 67,000
Scientist GINR 37,400 – 67,000
Scientist HINR 67,000 – 79,000
Distinguished ScientistINR 75,000 – 80,000
Secretary DRDO, DG, R&D, and Scientific  AdvisorINR 80,000 and up

Salary after CSIR NET JRF

The candidate, after qualifying for the examination, will get a fellowship of Rs. 31000/-, which includes HRA per month (CSIR institutes), given to the selected candidates for two years.

 A fellowship of Rs.35000/- also includes HRA per month (CSIR institutes) will be given to the selected candidates for three years.

CSIR NET Assistant Professor Salary

Candidates can expect to pay in the range of Rs. 30, 000/- to 40, 000/- per month in the starting phase based on the college/institutes.

PositionExpected Salary (Monthly in INR)
Junior Research Fellows31,000 +HRA (Depends on the Institution)
Senior Research Fellows35,000+HRA (Depends on the Institution)
Assistant Professor45,000
Associate Professor80,000
Professor82,000

CSIR UGC NET Syllabus

The NET syllabus has been made public by the CSIR on their official website. Candidates who plan to take the exam can download the PDF for the course materials for each of the five subjects and use them offline. The CSIR NET exam consists of three parts, A, B, and C. The Part A syllabus is the same for everyone, while the Part B and C syllabuses are entirely dependent on the candidates’ chosen subjects. Candidates can choose the subject when completing their online application.

The CSIR NET Syllabus is a collection of topics from various subjects for which the exam is given. All applicants must be familiar with the exam topics in order to improve their chances of selection. Part-A is based on General Science, Quantitative Reasoning & Analysis, and Research Aptitude. Part-B is based on the concerned subject and Part- C is based on the scientific concepts or their applications.

CSIR – UGC NET Subjects

SubjectsCodes
Chemical Science701
Earth, Atmospheric, Ocean, and Planetary Science702
Life Science703
Mathematical Science704
Physical Science705

Details of the CSIR NET Syllabus 2022

Chemical SciencesEarth, Atmospheric, Ocean & Planetary SciencesLife SciencesMathematical SciencesPhysical Sciences
Branches of ChemistryOceans and AtmosphereCellular OrganizationAnalysisMathematical Methods of Physics
Organic ChemistryEnvironmental Earth SciencesInheritance BiologyAlgebraAtomic & Molecular Physics
Inorganic ChemistryMineralogy and PetrologyDevelopmental BiologyClassical MechanicsElectromagnetic Theory
Medicinal ChemistryThe Earth and the Solar SystemMolecules and their Interaction Relevant to Biology Linear Integral EquationsThermodynamic and Statistical Physics
Physical ChemistryEarth Materials, Surface Features and ProcessesApplied BiologyCalculus of VariationsNuclear and Particle Physics
Catalysis and Green ChemistryGeophysicsDiversityPartial Differential Equations (PDEs)Condensed Matter Physics
Chemistry in Nanoscience and TechnologyPalaeontology and its applicationsFundamental ProcessesNumerical AnalysisQuantum Mechanics
Supramolecular ChemistryMarine Geology and PalaeontologyEvolution and BehaviourOrdinary Differential Equations (ODEs)Electronics and Experimental Methods

CSIR UGC NET Exam Pattern

Not only is filling out the application form sufficient, but the candidate needs to prepare bright enough, hence only after the candidate can beat the competitor. Therefore, not only to make your hunt easy but also to give you a complete overview. Below is the exam pattern, however, as per last year and for reference purposes only.

  • Mode of Language – CSIR-UGC NET exam gives the candidate options of choosing the language when filling out the application form. Therefore, the candidate can choose Hindi or English language as the mode of writing the paper.
  • Mode of Examination – CSIR-UGC NET 2022 execution is a Computer-based test (CBT).  
  • Overall Sections – The paper consists of three sections in the examination.
  • Question Type – Candidates have to answer the questions in Multiple Choice Questions (MCQ) way.
  • Duration of Examination – The candidate will be given 3 hours. i.e., 180 minutes to solve the three sections of the examination paper.

Particulars

Exam Pattern

Exam mode

Online

Language of paper

English and Hindi

Exam duration

180 minutes (3 hours)

Number of sections/parts

3

Type of questions

MCQs

Number of subjects

5

Total questions to be attempted

Chemical Sciences: 75

Earth Sciences: 75

Life Sciences: 75

Mathematical Sciences: 60

Physical Sciences: 55

Total marks

200 for each paper

Marking scheme

+2 for the correct answer

Negative marking of 25 per cent (33 per cent for some parts)

Exam Pattern for Chemical Sciences, Earth Sciences, Life Sciences:

Candidates for the CSIR NET Chemical Sciences paper must attempt a total of 75 MCQs from Parts A, B, and C. Each question in Parts A and B is worth two marks, while Part C questions are worth four. For incorrect answers, there is a 25% deduction from the final grade individually in reach subjects.

Exam Pattern for Mathematical Sciences:

Candidates must attempt 60 of the 120 MCQs in the CSIR NET Mathematical Sciences paper. The exam must be finished in three hours by the candidates. Part A questions are worth two points each, Part B questions are worth three points each, and Part C questions are worth four and a half points each. Each incorrect response receives a 25% deduction from the final score in Parts A and B, but there is no deduction in Part C.

Exam Pattern for Physical Sciences:

Candidates must attempt 55 out of the 75 MCQs in the CSIR NET Physical Sciences paper. Each question in Part A is worth two marks, while the weighted average for questions in Parts B and C is 3.5 and five marks, respectively. In Parts A, B, and C, there is a negative marking of 25% for each incorrect response.

CSIR UGC NET Admit Card

On its official website, NTA will soon release the CSIR NET Admit Card 2022. The admit card is made available 3–4 days prior to the exam, which is scheduled for September 16–19, 2022. Downloading the admit card requires the candidate to enter their registration number or date of birth. Admit card is the necessary document which candidates need to carry on the examination day. Hence, the candidate must carry it; otherwise, the candidature will get cancelled simultaneously. Admit card also contains all the essential information relating to the examination like examination date, examination center, name of the candidate, roll number of the candidate, last but not least, the date and time of the examination.

How to Download the CSIR UGC NET 2022 Admit Card?

Below are the steps that can help the candidate while downloading the admit card.

  1. Go to the official website.
  2. Click on the Download Admit Card link/tab from the homepage candidate.
  3. Enter application number, date of birth/ password, and security code.
  4. Log in to download the admit card.
  5. Take the admit card print and check all the details written in it.

Documents should be carried along with admit card

Candidates must bring one photo ID proof on the day of the exam in addition to their CSIR NET 2022 admission card for verification purposes. The list of acceptable ID documents is provided below:

  1. One passport-size photograph.
  2. Driving licence, voter ID card, PAN card, passport, and Adhaar card
  3. Employee ID card
  4. Photo ID cards from the federal, state, or university/college governments.
  5. If claiming the relaxation under the PwD category, a PwD certificate issued by the Competent Authority is required (Mandatory, if applicable).

CSIR NET Exam Centre 

The National Testing Agency has published the cities where the CSIR NET exam will be held in 2022. (NTA). When completing the online application form, candidates had to choose the city where they wanted to take the CSIR NET exam. The release of the admit card will contain information regarding the precise name and address of the CSIR NET exam centre for 2022.

List of centers

Andaman And Nicobar

Port Blair

Andhra Pradesh

Anantapur

Bhimavaram

Chirala

Chittoor

Eluru

Guntur

Kadapa

Kakinada

Kurnool

Narasaraopeta

Nellore

Ongole

Proddatur

Rajahmundry

Srikakulam

Surampallem

Tirupathi

Vijayawada

Visakhapatnam

Vizianagaram

Arunachal Pradesh

Itanagar/Naharlagun

Assam

Dibrugarh

Guwahati

Jorhat

Silchar (Assam)

Tezpur

Bihar

Arrah

Bhagalpur

Darbhanga

Gaya

Muzzafarpur

Patna

Purnea

Chandigarh

Chandigarh/Mohali/ Panchkula

Chhattisgarh

Bhilai Nagar/Durg

Bilaspur (Chhattisgarh)

Raipur

Dadra & Nagar Haveli

Dadra & Nagar Haveli

Daman & Diu

Daman

Diu

Delhi

New Delhi

Goa

Panaji/Madgaon

Gujarat

Ahmedabad / Gandhinagar

Anand

Bhavnagar

Himatnagar

Jamnagar

Junagadh

Mehsana

Rajkot

Surat

Vadodara

Vapi

Haryana

Ambala

Faridabad

Gurugram

Hisar

Karnal

Kurukshetra

Panipat

Sonipat

Yamuna Nagar

Himachal Pradesh

Bilaspur

Hamirpur

Kangra

Kullu

Mandi

Shimla

Solan

Una

Jammu And Kashmir

Baramulla

Jammu

Samba

Srinagar

Jharkhand

Bokaro Steel City

Dhanbad

Hazaribagh

Jamshedpur

Ranchi

Karnataka

Belagavi(Belgaum)

Bellary

Bengaluru

Bidar

Davanagere

Dharwad/Hubballi(Hubli)

Gulbarga

Hassan

Mandya

Mangaluru(Mangalore)

Mysuru(Mysore)

Shivamoga(Shimoga)

Tumakuru

Udupi/Manipal

Kerala

Alappuzha

Ernakulam

Idukki

Kannur

Kasaragod

Kollam

Kottayam

Kozhikode

Malappuram

Palakkad

Pathanamthitta

Thiruvananthapuram

Thrissur

Ladakh

Leh

Lakshadweep

Kavaratti

Madhya Pradesh

Balaghat

Betul

Bhopal

Chhindwara

Gwalior

Indore

Jabalpur

Rewa

Sagar

Satna

Ujjain

Maharashtra

Ahmednagar

Akola

Amravati

Aurangabad

Chandrapur

Dhule

Jalgaon

Kolhapur

Latur

Mumbai/Navi Mumbai

Nagpur

Nanded

Nashik

Pune

Raigad

Ratnagiri

Sangli

Satara

Solapur

Thane

Wardha

Manipur

Churachandpur

Imphal

Meghalaya

Shillong

Mizoram

Aizawl

Nagaland

Dimapur

Kohima

Odisha

Balasore

Berhampur-Ganjam

Bhubaneswar

Cuttack

Dhenkanal

Rourkela

Sambalpur

Puducherry

Puducherry

Punjab

Amritsar

Bhatinda

Jalandhar

Ludhiana

Pathankot

Patiala/ Fatehgarh Sahib

Sangrur

Rajasthan

Ajmer

Alwar

Bikaner

Jaipur

Jodhpur

Kota

Sikar

Sriganganagar

Udaipur

Sikkim

Gangtok

Tamil Nadu

Chennai

Coimbatore

Cuddalore

Kanchipuram

Kanyakumari/Nagercoil

Madurai

Namakkal

Salem

Thanjavur

Thoothukudi

Tiruchirappalli

Tirunelveli

Tiruvallur

Vellore

Virudhunagar

Telangana

Hyderabad

Karimnagar

Khammam

Mahbubnagar

Nalgonda

Warangal

Tripura

Agartala

Uttar Pradesh

Agra

Aligarh

Ayodhya

Bareilly

Ghaziabad

Gorakhpur

Jhansi

Kanpur

Lucknow

Mathura

Meerut

Moradabad

Muzaffarnagar

Noida / Greater Noida

Prayagraj

Sitapur

Varanasi

Uttarakhand

Dehradun

Haldwani

Haridwar

Nainital

Pantnagar

Roorkee

West Bengal

Asansol

Burdwan

Durgapur

Hooghly

Howrah

Kalyani

Kolkata

Siliguri

CSIR UGC NET Result

The conducting body has not yet disclosed the CSIR NET result date. But if past years are any indication, the CSIR NET result will be revealed a month after the test has been completed. The National Testing Agency (NTA) will first release the CSIR NET result for 2022, followed by the Council of Scientific and Industrial Research (CSIR). Examinees can access the CSIR NET results by logging in with their application number and birthdate. The distribution of the CSIR NET e-certificate 2022 will be based on the final results announced by the CSIR. Here are some points that candidates need to keep in mind:

  • The CSIR-UG NET result releases in the form of a merit list which carries the candidate’s roll number and the name of the qualifying candidates.
  • Candidates can likewise check the CSIR NET Scorecard. Finally, they will need to visit the site and sign in by entering their login details like their application number and DOB.
  • Applicants are qualified to be named for the Assistant Professorship and Junior Research Fellowship jobs upon qualifying for the examination.

How to Check CSIR NET Result 2022?

Candidates can use the steps listed below to check their CSIR UGC NET 2022 result:

Step 1: Go to the CSIR NET website.

Step 2: Select the link “Joint CSIR UGC NET June 2022 Score Card.”

Step 3: Provide the following information- Application number, Date of birth and Security pin as shown in the image.

Step 4: Click on “Submit.”

Step 5: View and download the CSIR NET scorecard and result.

Details in the CSIR NET Exam Results to be verified

The following information is included in the CSIR results, which applicants are urged to carefully review. It might contain details like the ones listed below:

  1. Name of the candidate
  2. Candidate’s roll number
  3. candidate’s position/ rank
  4. Total number of candidates who are qualified
  5. Whether he or she passed or failed, etc.

Merit List

The CSIR UGC NET 2022 Merit List will be determined by taking into account the total marks across all parts. All applicants who meet the requirements for a Junior Research Fellowship are given ranks. Below are some key details regarding the CSIR UGC NET Merit List: –

  • NTA releases two separate merit lists comprising the names of the candidates qualifying for the Junior Research Fellowship (JRF-NET) and Lectureship (LS-NET).
  • CSIR-UGC NET Merit list carries specified details of the examinee such as the Roll Number of the candidate, Rank obtained and Marks secured.
  • NTA prepares merit list overall on the basis of the performance of candidates in the entrance test.
  • Candidates who qualify for the examination will further get the opportunity for lectureship if fulfil eligibility criteria.
  • Qualified examinees for Lectureship will be eligible to be considered for recruitment as a Junior Research Fellowship if they match all the eligibility criteria and norms. However, candidates will not be eligible for the regular JRF-NET Fellowship.
  • Candidates qualifying for JRF (NET) will receive fellowship from either CSIR or UGC as per their associated assignment.

Checking the CSIR UGC NET Merit List:

Step 1: Visit the CSIR’s official website.

Step 2: Go to the CSIR UGC NET Exam header and select the CSIR NET Result link.

Step 3: Download and save the merit list at this time.

CSIR UGC NET Cut Off 2022

The CSIR NET Cut Off is the score at which candidates will be chosen for JRF and Lectureship positions. In order to pass the CSIR NET exam, candidates must score at least 33% in the General, EWS, and OBC categories and 25% in the SC, ST, and PwD categories. There are three parts to the CSIR UGC NET: Parts A, B, and C. However, there are no sectional cut-offs; instead, the cut-off is determined by adding the marks obtained in each component. . The cut-off marks vary for both the categories, Junior Research Fellowship (JRF) and Lectureship.

CSIR NET JRF Cut-off (Expected)
Subject UR (%) EWS (%) OBC (%) SC (%) ST (%) PWD (%)
Chemical Science 52.75 46.25 45.5 36.25 27.25 25
Earth Science 60.86 54.79 53.06 46.4 42.81 26.4
Life Science 98.78 96.06 96.22 90.53 84.87 64.76
Mathematical Science 49.25 44.87 42.75 34.37 27 25
Physical Science 38.81 33 33 25 25 25

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FAQs

Q.1 How to recover CSIR UGC NET roll number?

Ans. Candidates can retrieve their UGC NET application number or password for NTA UGC NET 2022 online at ugcnet.nta.nic.in if they have forgotten it. To retrieve your UGC NET Application Number/Roll Number or Password, follow the steps listed below:

  1. Visit the official website.
  2. Select the button for the application form.
  3. Select the link labelled “Forgot Application Number.”
  4. Enter name, father’s name, mother’s name and date of birth.
  5. Enter the security pin shown on the screen.
  6. The “Get Application Number” button should be clicked.

Q.2 What is difference between UGC NET and CSIR NET?

Ans. The National Eligibility Test (NET), which is administered on behalf of University Grants Commission (UGC), is used to determine whether Indian citizens are eligible for assistant professor positions in Indian universities and colleges. NTA administers CSIR NET to select candidates for the JRF award and eligibility for assistant professor positions in science-only fields. NTA administers UGC NET to choose candidates for JRF awards and eligibility for assistant professor positions in all other subjects (total 81).

Q.3 Which is tough UGC NET or CSIR NET?

Ans. The CSIR NET exam is considered to be highly competitive and tough. While studying for the exam, you gain a lot of knowledge and experience, so passing it is not just like having a degree. With others, you can impart your wisdom and experience. Candidates who pass the CSIR-UGC NET examination have the option of applying for junior research fellowships and teaching positions. The NET exam is held twice a year, in June and December, by NTA on behalf of UGC. To sit for this exam, candidates must have earned a minimum of 55% on their Master’s degree. Candidates who pass the UGC-NET exam are eligible for lecturer positions at IITs and NITs as well as research programmes (JRF).

Q.4 What is NTA score in CSIR UGC NET?

Ans. The overall NTA score represents the proportion of candidates who in that session scored EQUAL TO OR BELOW (same or lower raw scores) that specific candidate. It says nothing about your qualification or lack thereof. Most likely, the cut-off will be the same as last year. But it should be increase by 5 marks (Not percentage). According to the CSIR NET answer key, marks will be awarded for accurate responses. The “NTA score” or percentile will be created from this raw score. All candidates’ scores will be combined to create the final merit list.

Q.5 When will I get CSIR UGC NET certificate?

Ans. 4-5 months after the results are announced, UGC and CSIR upload the certificate. Candidates who qualify for lectureships and research positions as JRFS in Indian universities are given this certificate. To download CSIR certificates, follow these simple steps: UGC NET Certificate Download (Part I)

Step 1: Sign in to the CSIR website.

Step 2: enter the required details as mentioned on the website and press the “submit” button.

Step 3: Download the CSIR certificate visible on the screen. Print the hard copy later for your records.

Download UGC NET Certificate (Part II and III)

Step 1: Access the UGC website.

Step 2: Press the button to download the CSIR-UGC Test e-certificate.

Step 3: There will then be a “Yes” or “No” option for you to select.

Step 4: Click “Yes” if you already have your password via OTP.

Step 5: If you haven’t received the password via OTP, choose No.

Step 6: Subsequently, complete all the necessary information and download the certificate.

Q.6 How to prepare for CSIR UGC NET physics?

Ans. The Candidates for the CSIR NET Physics Section Part-B only need to concentrate on the fundamental ideas of physics that they have already studied at the 10+2 level. If candidates are very well prepared for this section, this part could be very scoring. The candidates should go over the crucial subjects first, followed by the others, in order to prepare properly. The key to answering the numerical problems is clearly understanding the question. It is important to be clear about what is given in the problem and what is asked because a problem that is well-defined is already halfway solved. In order to better understand a particular theorem, try to solve and remember some of the problems where it is used.