The National Testing Agency leads CSIR UGC NET on the Council of Scientific and Industrial Research (CSIR) mandates. In order to determine whether Indian citizens are qualified for Junior Research Fellowships (JRF) and Lectureships (LS)/Assistant Professor Positions in Indian universities and colleges, the Joint CSIR UGC NET test is being administered. For training in research techniques under the expert supervision of professors and scientists working in university departments, national laboratories, and institutions across a range of scientific disciplines, CSIR and UGC offer Research Fellowships.
The exam is also known as CSIR NET. It’s a National Level exam conducted by the NTA. CSIR – UGC Net is done in CBT (Computer Based Test) mode only. For JRF and LS/AP CSIR, CSIR NET online applications are made available twice a year via CSIR Press Notification on all Indian CSIR UGC NET websites. Under the expert direction of faculty or researchers working in university departments, national laboratories, and institutions across a variety of scientific fields, UGC offers Research Fellowships to train techniques for research. Only legitimate Indian citizens are permitted to take the exam. NTA CSIR NET Fellowship is a workable remedy in India. The development of national science and technology human resources is the aim of this program.
Candidates who pass the exam will be qualified to apply for the position of Lecturer in the discipline under the faculty of Science and Technology at various universities and colleges in India. The candidates who meet the requirements for the Junior Research Fellowship (JRF) will be eligible to apply for a PhD in their chosen fields at various Indian universities. JRF students are eligible for a variety of benefits, including stipends, HRAs, and others.
For the first two years, a JRF selected through CSIR-NET will receive a stipend of Rs.31, 000 per month. A yearly contingent grant of Rs.20, 000 will also be given to the university or institution for each fellow. The terms and conditions of the CSIR, UGC, or Research Scheme, as appropriate, will govern the Fellowship. The Fellowship will be upgraded to SRF (NET) upon completion of two years as JRF and if the Fellow is enrolled in a Ph.D., and the stipend will be increased to Rs. 35,000/- per month for the third and subsequent years, on the basis of assessment of the Fellows’ research progress/achievements through interview by an Expert Committee consisting of the Guide, Head of the Department, and External Member from outside the University/Institute who is an expert in the relevant field.
| Particulars | Details |
| Examination Name | CSIR-UGC NET |
| Exam Conducting Body | NTA (National Testing Agency) |
| Examination Level | National |
| Posts Offering | Junior Research Fellowship and Lectureship |
| Examination Mode | Online |
| Periodicity(No. of time) | Twice a year – June and December |
| Application Mode | Online |
| Examination Mode | Computer Based Test (CBT)Online |
| Language of Paper | English and Hindi |
| No. of Test Cities | 225 |
| Helpdesk No. | 0120-6895200 |
| Official Website | http://csirnet.nta.nic.in, http://nta.ac.in/ |
The candidates who are going to appear in CSIR UGC NET 2022 exam must know the selection process of the examination. Hence, only then can they understand that the step-by-step guide of the CSIR UGC NET selection process consists of the following stages given below:
| Junior Research Fellow | 2022 list of selected students in UGC NET exam (General Category) for Lectureship in English Subject | The number of candidates (General category) who secure a minimum of 40% aggregate marks in papers 1 & 2 taken for ‘English’ (x) Total number of slots available under General category (÷) Total number of candidates (General category) overall subjects who secure at least 40% aggregate marks in both papers combined. |
| Lectureship | List of selected students in UGC NET exam(General Category) for Lectureship in English Subject | The number of candidates (General category) who secure a minimum of 40% aggregate marks in papers 1 & 2 taken for ‘English’ (x) Total number of slots available under General category (÷) Total number of candidates (General category) overall subjects who secure at least 40% aggregate marks in both papers combined. |
The minimum score required to pass the UGC NET exam are given below:
On 11th July 2022, the NTA made the CSIR NET 2022 announcement. The CSIR NET notification for 2022 has been made available on the National Testing Agency’s (NTA) official website, csirnet.nta.nic.in. The notification includes all of the crucial exam information, including the thorough application process, eligibility requirements, admit card, exam dates, exam schedule, syllabus, and others.
Three to four days before the test, the CSIR NET admit card for 2022 will be made available. From 11th July to 17th August 2022, candidates who wanted to be eligible for JRF and Lectureship/ Assistant Professor positions in Indian universities and colleges could apply for the CSIR NET.
The CSIR NET exam date has been mentioned below in the table:
| Events | Dates |
| CSIR UGC NET Notification | 11th July 2022 |
| CSIR UGC NET Online Applications Starts | 11th July to 10th August 2022 |
| Last date for payment of the application fee | 17th August 2022 |
| Online Applications Correction Window | 19th August to 23rd August 2022 |
| CSIR UGC NET Admit card 2022 | To be Announced |
| CSIR UGC NET exam 2022 | 16th September to 19th September 2022 |
| CSIR UGC NET Result declaration 2022 | To be Announced |
| Provisional Answer Key | To be Announced |
| Cut off | To be Announced |
The four stages of the CSIR NET application for 2022 are registration, application, document upload, and fee payment. Candidates are advised to confirm that they meet the CSIR NET eligibility requirements 2022 before submitting their application for the CSIR NET 2022 exam.
The steps listed below must be followed by candidates in order to register online:
Candidates must click the “Complete Application Form” button to continue filling out the CSIR UGC NET online application. Candidates need to fill the details like their personal details, educational qualification, exam center city, medium of exam, doctorate details (if any), etc.
Candidates must upload scanned copies of their photo and signature that adhere to the requirements.
The CSIR UGC NET 2022 application fee must be paid online via a debit card, credit card, net banking, UPI, or Paytm gateway.
Most importantly, there is an application fee for the candidates who want to appear in the CSIR-UGC NET 2022 exam. The examination conducting body accepts applications and the application fees through online mode only. The application fees can be submitted online through the official website only after filling out the application form.
Therefore, candidates must check all the information one more time before hitting the submit button while paying the application fee. The table below lists the application fees for various categories:
| Category | Application fee (Rs) |
| General | Rs 1000 |
| EWS | Rs 500 |
| OBC (Non-Creamy Layer) | Rs 500 |
| SC/ST/PD | Rs 250 |
| PWD | Rs 250 |
| Transgender | Rs 250 |
Candidates who wish to register for the CSIR-UGC NET 2022 examination must check the eligibility criteria. Those who fill out the form without passing the eligibility criteria will not download the admit card as they will fail the eligibility criteria. It’s essential to match the eligibility criteria if you wish to sit for the examination. The basic criteria are based on JRF age limit and educational qualifications.
The council establishes eligibility based on exam requirements and to ensure that all applicants have an equal chance.
The age should be calculated as of 01st July, 2022.
|
Profile |
Upper Age Limit |
||
|
Reserved Category |
SC/ST/PWD |
OBC (NCL) |
|
|
JRF |
28 years |
33 years |
31 years |
|
Assistant Professor |
There is no Upper Age Limit |
||
| For General Category | Candidates must have at least 55% marks in M.Sc. or Integrated BS-MS |
| For SC/ST/OBC Category | Candidates of the SC/ST/OBC category must have a minimum score of 50% in M.Sc. or B.Sc. with admission in Integrated MS-PhD. |
|
CSIR NET Subject-wise Qualification |
|
|
Life Science |
Pursued academic qualification in Life Science only. |
|
Chemical Sciences |
Have an M.Sc./BS/B-Tech or similar degree in Chemistry with the required percentage. |
|
Earth Sciences |
Within the required qualifying criteria, pursued an M.Sc./BS-MS/BS-4 Years/B-Pharma or any similar degree in the subject of Earth Science. |
|
Mathematical Sciences |
To meet the qualifying requirements, must have an M.Sc./BS-MS/BS-4 Years//B-Tech or an equivalent degree in mathematics. |
|
Physical Sciences |
Have a valid M.Sc. Physics or BS-MS in Physics degree, or any equivalent degree within the required percentage. |
Number of attempts: There is no restriction on the number of attempts for the CSIR NET Exam provided candidates satisfy the eligibility criteria mentioned above.
In particular, the Bhabha Atomic Research Centre (BARC), the National Environmental Engineering Research Institute (NEERI), the Indian Space Research Organization (ISRO), and the Council of Scientific & Industrial Research (CSIR), IMTECH, NBRI, ICAR, IGCAR itself can be entered after passing the NTA CSIR NET. Candidates can apply to different scientist grades like Scientist B, Scientist C, and Scientist D, career in managerial positions, conduct research for esteemed organisations, or develop and test products in the fields of medicine, pharmaceuticals, and consumer research. Below is a detailed list of the various grades of scientists and their pay scale:
| Designation/ Position | Pay range/ Scale |
| Scientist B | INR 15,600 – 39,100 |
| Scientist C | INR 15,600 – 39,100 |
| Scientist D | INR 15,600 – 39,100 |
| Scientist E | INR 37,400 – 67,000 |
| Scientist F | INR 37,400 – 67,000 |
| Scientist G | INR 37,400 – 67,000 |
| Scientist H | INR 67,000 – 79,000 |
| Distinguished Scientist | INR 75,000 – 80,000 |
| Secretary DRDO, DG, R&D, and Scientific Advisor | INR 80,000 and up |
Salary after CSIR NET JRF
The candidate, after qualifying for the examination, will get a fellowship of Rs. 31000/-, which includes HRA per month (CSIR institutes), given to the selected candidates for two years.
A fellowship of Rs.35000/- also includes HRA per month (CSIR institutes) will be given to the selected candidates for three years.
CSIR NET Assistant Professor Salary
Candidates can expect to pay in the range of Rs. 30, 000/- to 40, 000/- per month in the starting phase based on the college/institutes.
| Position | Expected Salary (Monthly in INR) |
| Junior Research Fellows | 31,000 +HRA (Depends on the Institution) |
| Senior Research Fellows | 35,000+HRA (Depends on the Institution) |
| Assistant Professor | 45,000 |
| Associate Professor | 80,000 |
| Professor | 82,000 |
The NET syllabus has been made public by the CSIR on their official website. Candidates who plan to take the exam can download the PDF for the course materials for each of the five subjects and use them offline. The CSIR NET exam consists of three parts, A, B, and C. The Part A syllabus is the same for everyone, while the Part B and C syllabuses are entirely dependent on the candidates’ chosen subjects. Candidates can choose the subject when completing their online application.
The CSIR NET Syllabus is a collection of topics from various subjects for which the exam is given. All applicants must be familiar with the exam topics in order to improve their chances of selection. Part-A is based on General Science, Quantitative Reasoning & Analysis, and Research Aptitude. Part-B is based on the concerned subject and Part- C is based on the scientific concepts or their applications.
| Subjects | Codes |
| Chemical Science | 701 |
| Earth, Atmospheric, Ocean, and Planetary Science | 702 |
| Life Science | 703 |
| Mathematical Science | 704 |
| Physical Science | 705 |
| Chemical Sciences | Earth, Atmospheric, Ocean & Planetary Sciences | Life Sciences | Mathematical Sciences | Physical Sciences |
| Branches of Chemistry | Oceans and Atmosphere | Cellular Organization | Analysis | Mathematical Methods of Physics |
| Organic Chemistry | Environmental Earth Sciences | Inheritance Biology | Algebra | Atomic & Molecular Physics |
| Inorganic Chemistry | Mineralogy and Petrology | Developmental Biology | Classical Mechanics | Electromagnetic Theory |
| Medicinal Chemistry | The Earth and the Solar System | Molecules and their Interaction Relevant to Biology | Linear Integral Equations | Thermodynamic and Statistical Physics |
| Physical Chemistry | Earth Materials, Surface Features and Processes | Applied Biology | Calculus of Variations | Nuclear and Particle Physics |
| Catalysis and Green Chemistry | Geophysics | Diversity | Partial Differential Equations (PDEs) | Condensed Matter Physics |
| Chemistry in Nanoscience and Technology | Palaeontology and its applications | Fundamental Processes | Numerical Analysis | Quantum Mechanics |
| Supramolecular Chemistry | Marine Geology and Palaeontology | Evolution and Behaviour | Ordinary Differential Equations (ODEs) | Electronics and Experimental Methods |
Not only is filling out the application form sufficient, but the candidate needs to prepare bright enough, hence only after the candidate can beat the competitor. Therefore, not only to make your hunt easy but also to give you a complete overview. Below is the exam pattern, however, as per last year and for reference purposes only.
|
Particulars |
Exam Pattern |
|
Exam mode |
Online |
|
Language of paper |
English and Hindi |
|
Exam duration |
180 minutes (3 hours) |
|
Number of sections/parts |
3 |
|
Type of questions |
MCQs |
|
Number of subjects |
5 |
|
Total questions to be attempted |
Chemical Sciences: 75 |
|
Earth Sciences: 75 |
|
|
Life Sciences: 75 |
|
|
Mathematical Sciences: 60 |
|
|
Physical Sciences: 55 |
|
|
Total marks |
200 for each paper |
|
Marking scheme |
+2 for the correct answer Negative marking of 25 per cent (33 per cent for some parts) |
Candidates for the CSIR NET Chemical Sciences paper must attempt a total of 75 MCQs from Parts A, B, and C. Each question in Parts A and B is worth two marks, while Part C questions are worth four. For incorrect answers, there is a 25% deduction from the final grade individually in reach subjects.
Candidates must attempt 60 of the 120 MCQs in the CSIR NET Mathematical Sciences paper. The exam must be finished in three hours by the candidates. Part A questions are worth two points each, Part B questions are worth three points each, and Part C questions are worth four and a half points each. Each incorrect response receives a 25% deduction from the final score in Parts A and B, but there is no deduction in Part C.
Candidates must attempt 55 out of the 75 MCQs in the CSIR NET Physical Sciences paper. Each question in Part A is worth two marks, while the weighted average for questions in Parts B and C is 3.5 and five marks, respectively. In Parts A, B, and C, there is a negative marking of 25% for each incorrect response.
On its official website, NTA will soon release the CSIR NET Admit Card 2022. The admit card is made available 3–4 days prior to the exam, which is scheduled for September 16–19, 2022. Downloading the admit card requires the candidate to enter their registration number or date of birth. Admit card is the necessary document which candidates need to carry on the examination day. Hence, the candidate must carry it; otherwise, the candidature will get cancelled simultaneously. Admit card also contains all the essential information relating to the examination like examination date, examination center, name of the candidate, roll number of the candidate, last but not least, the date and time of the examination.
Below are the steps that can help the candidate while downloading the admit card.
Candidates must bring one photo ID proof on the day of the exam in addition to their CSIR NET 2022 admission card for verification purposes. The list of acceptable ID documents is provided below:
The National Testing Agency has published the cities where the CSIR NET exam will be held in 2022. (NTA). When completing the online application form, candidates had to choose the city where they wanted to take the CSIR NET exam. The release of the admit card will contain information regarding the precise name and address of the CSIR NET exam centre for 2022.
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List of centers |
|
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Andaman And Nicobar |
Port Blair |
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Andhra Pradesh |
Anantapur |
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Bhimavaram |
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Chirala |
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Chittoor |
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Eluru |
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Guntur |
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Kadapa |
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Kakinada |
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Kurnool |
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Narasaraopeta |
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Nellore |
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Ongole |
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Proddatur |
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Rajahmundry |
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Srikakulam |
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Surampallem |
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Tirupathi |
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Vijayawada |
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Visakhapatnam |
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Vizianagaram |
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Arunachal Pradesh |
Itanagar/Naharlagun |
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Assam |
Dibrugarh |
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Guwahati |
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Jorhat |
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Silchar (Assam) |
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Tezpur |
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Bihar |
Arrah |
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Bhagalpur |
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Darbhanga |
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Gaya |
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Muzzafarpur |
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Patna |
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Purnea |
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Chandigarh |
Chandigarh/Mohali/ Panchkula |
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Chhattisgarh |
Bhilai Nagar/Durg |
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Bilaspur (Chhattisgarh) |
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Raipur |
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Dadra & Nagar Haveli |
Dadra & Nagar Haveli |
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Daman & Diu |
Daman |
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Diu |
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Delhi |
New Delhi |
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Goa |
Panaji/Madgaon |
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Gujarat |
Ahmedabad / Gandhinagar |
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Anand |
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Bhavnagar |
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Himatnagar |
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Jamnagar |
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Junagadh |
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Mehsana |
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Rajkot |
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Surat |
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Vadodara |
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Vapi |
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Haryana |
Ambala |
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Faridabad |
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Gurugram |
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Hisar |
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Karnal |
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Kurukshetra |
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Panipat |
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Sonipat |
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Yamuna Nagar |
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Himachal Pradesh |
Bilaspur |
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Hamirpur |
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Kangra |
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Kullu |
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Mandi |
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Shimla |
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Solan |
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Una |
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Jammu And Kashmir |
Baramulla |
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Jammu |
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Samba |
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Srinagar |
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Jharkhand |
Bokaro Steel City |
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Dhanbad |
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Hazaribagh |
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Jamshedpur |
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Ranchi |
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Karnataka |
Belagavi(Belgaum) |
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Bellary |
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Bengaluru |
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Bidar |
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Davanagere |
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Dharwad/Hubballi(Hubli) |
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Gulbarga |
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Hassan |
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Mandya |
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Mangaluru(Mangalore) |
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Mysuru(Mysore) |
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Shivamoga(Shimoga) |
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Tumakuru |
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Udupi/Manipal |
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Kerala |
Alappuzha |
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Ernakulam |
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Idukki |
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Kannur |
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Kasaragod |
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Kollam |
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Kottayam |
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Kozhikode |
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Malappuram |
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Palakkad |
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Pathanamthitta |
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Thiruvananthapuram |
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Thrissur |
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Ladakh |
Leh |
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Lakshadweep |
Kavaratti |
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Madhya Pradesh |
Balaghat |
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Betul |
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Bhopal |
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Chhindwara |
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Gwalior |
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Indore |
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Jabalpur |
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Rewa |
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Sagar |
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Satna |
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Ujjain |
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Maharashtra |
Ahmednagar |
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Akola |
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Amravati |
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Aurangabad |
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Chandrapur |
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Dhule |
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Jalgaon |
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Kolhapur |
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Latur |
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Mumbai/Navi Mumbai |
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Nagpur |
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Nanded |
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Nashik |
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Pune |
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Raigad |
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Ratnagiri |
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Sangli |
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Satara |
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Solapur |
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Thane |
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Wardha |
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Manipur |
Churachandpur |
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Imphal |
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Meghalaya |
Shillong |
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Mizoram |
Aizawl |
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Nagaland |
Dimapur |
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Kohima |
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Odisha |
Balasore |
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Berhampur-Ganjam |
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Bhubaneswar |
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Cuttack |
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Dhenkanal |
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Rourkela |
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Sambalpur |
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Puducherry |
Puducherry |
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Punjab |
Amritsar |
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Bhatinda |
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Jalandhar |
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Ludhiana |
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Pathankot |
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Patiala/ Fatehgarh Sahib |
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Sangrur |
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Rajasthan |
Ajmer |
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Alwar |
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Bikaner |
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Jaipur |
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Jodhpur |
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Kota |
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Sikar |
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Sriganganagar |
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Udaipur |
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Sikkim |
Gangtok |
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Tamil Nadu |
Chennai |
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Coimbatore |
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Cuddalore |
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Kanchipuram |
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Kanyakumari/Nagercoil |
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Madurai |
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Namakkal |
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Salem |
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Thanjavur |
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Thoothukudi |
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Tiruchirappalli |
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Tirunelveli |
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Tiruvallur |
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Vellore |
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Virudhunagar |
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Telangana |
Hyderabad |
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Karimnagar |
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Khammam |
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Mahbubnagar |
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Nalgonda |
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Warangal |
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Tripura |
Agartala |
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Uttar Pradesh |
Agra |
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Aligarh |
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Ayodhya |
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Bareilly |
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Ghaziabad |
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Gorakhpur |
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Jhansi |
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Kanpur |
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Lucknow |
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Mathura |
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Meerut |
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Moradabad |
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Muzaffarnagar |
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Noida / Greater Noida |
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Prayagraj |
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Sitapur |
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Varanasi |
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Uttarakhand |
Dehradun |
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Haldwani |
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Haridwar |
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Nainital |
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Pantnagar |
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Roorkee |
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West Bengal |
Asansol |
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Burdwan |
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Durgapur |
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Hooghly |
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Howrah |
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Kalyani |
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Kolkata |
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Siliguri |
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The conducting body has not yet disclosed the CSIR NET result date. But if past years are any indication, the CSIR NET result will be revealed a month after the test has been completed. The National Testing Agency (NTA) will first release the CSIR NET result for 2022, followed by the Council of Scientific and Industrial Research (CSIR). Examinees can access the CSIR NET results by logging in with their application number and birthdate. The distribution of the CSIR NET e-certificate 2022 will be based on the final results announced by the CSIR. Here are some points that candidates need to keep in mind:
Candidates can use the steps listed below to check their CSIR UGC NET 2022 result:
Step 1: Go to the CSIR NET website.
Step 2: Select the link “Joint CSIR UGC NET June 2022 Score Card.”
Step 3: Provide the following information- Application number, Date of birth and Security pin as shown in the image.
Step 4: Click on “Submit.”
Step 5: View and download the CSIR NET scorecard and result.
The following information is included in the CSIR results, which applicants are urged to carefully review. It might contain details like the ones listed below:
The CSIR UGC NET 2022 Merit List will be determined by taking into account the total marks across all parts. All applicants who meet the requirements for a Junior Research Fellowship are given ranks. Below are some key details regarding the CSIR UGC NET Merit List: –
Step 1: Visit the CSIR’s official website.
Step 2: Go to the CSIR UGC NET Exam header and select the CSIR NET Result link.
Step 3: Download and save the merit list at this time.
The CSIR NET Cut Off is the score at which candidates will be chosen for JRF and Lectureship positions. In order to pass the CSIR NET exam, candidates must score at least 33% in the General, EWS, and OBC categories and 25% in the SC, ST, and PwD categories. There are three parts to the CSIR UGC NET: Parts A, B, and C. However, there are no sectional cut-offs; instead, the cut-off is determined by adding the marks obtained in each component. . The cut-off marks vary for both the categories, Junior Research Fellowship (JRF) and Lectureship.
| CSIR NET JRF Cut-off (Expected) | ||||||
| Subject | UR (%) | EWS (%) | OBC (%) | SC (%) | ST (%) | PWD (%) |
| Chemical Science | 52.75 | 46.25 | 45.5 | 36.25 | 27.25 | 25 |
| Earth Science | 60.86 | 54.79 | 53.06 | 46.4 | 42.81 | 26.4 |
| Life Science | 98.78 | 96.06 | 96.22 | 90.53 | 84.87 | 64.76 |
| Mathematical Science | 49.25 | 44.87 | 42.75 | 34.37 | 27 | 25 |
| Physical Science | 38.81 | 33 | 33 | 25 | 25 | 25 |
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Ans. Candidates can retrieve their UGC NET application number or password for NTA UGC NET 2022 online at ugcnet.nta.nic.in if they have forgotten it. To retrieve your UGC NET Application Number/Roll Number or Password, follow the steps listed below:
Ans. The National Eligibility Test (NET), which is administered on behalf of University Grants Commission (UGC), is used to determine whether Indian citizens are eligible for assistant professor positions in Indian universities and colleges. NTA administers CSIR NET to select candidates for the JRF award and eligibility for assistant professor positions in science-only fields. NTA administers UGC NET to choose candidates for JRF awards and eligibility for assistant professor positions in all other subjects (total 81).
Ans. The CSIR NET exam is considered to be highly competitive and tough. While studying for the exam, you gain a lot of knowledge and experience, so passing it is not just like having a degree. With others, you can impart your wisdom and experience. Candidates who pass the CSIR-UGC NET examination have the option of applying for junior research fellowships and teaching positions. The NET exam is held twice a year, in June and December, by NTA on behalf of UGC. To sit for this exam, candidates must have earned a minimum of 55% on their Master’s degree. Candidates who pass the UGC-NET exam are eligible for lecturer positions at IITs and NITs as well as research programmes (JRF).
Ans. The overall NTA score represents the proportion of candidates who in that session scored EQUAL TO OR BELOW (same or lower raw scores) that specific candidate. It says nothing about your qualification or lack thereof. Most likely, the cut-off will be the same as last year. But it should be increase by 5 marks (Not percentage). According to the CSIR NET answer key, marks will be awarded for accurate responses. The “NTA score” or percentile will be created from this raw score. All candidates’ scores will be combined to create the final merit list.
Ans. 4-5 months after the results are announced, UGC and CSIR upload the certificate. Candidates who qualify for lectureships and research positions as JRFS in Indian universities are given this certificate. To download CSIR certificates, follow these simple steps: UGC NET Certificate Download (Part I)
Step 1: Sign in to the CSIR website.
Step 2: enter the required details as mentioned on the website and press the “submit” button.
Step 3: Download the CSIR certificate visible on the screen. Print the hard copy later for your records.
Download UGC NET Certificate (Part II and III)
Step 1: Access the UGC website.
Step 2: Press the button to download the CSIR-UGC Test e-certificate.
Step 3: There will then be a “Yes” or “No” option for you to select.
Step 4: Click “Yes” if you already have your password via OTP.
Step 5: If you haven’t received the password via OTP, choose No.
Step 6: Subsequently, complete all the necessary information and download the certificate.
Ans. The Candidates for the CSIR NET Physics Section Part-B only need to concentrate on the fundamental ideas of physics that they have already studied at the 10+2 level. If candidates are very well prepared for this section, this part could be very scoring. The candidates should go over the crucial subjects first, followed by the others, in order to prepare properly. The key to answering the numerical problems is clearly understanding the question. It is important to be clear about what is given in the problem and what is asked because a problem that is well-defined is already halfway solved. In order to better understand a particular theorem, try to solve and remember some of the problems where it is used.